Reduced cell
From Online Dictionary of Crystallography
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Revision as of 15:43, 18 December 2017 by MassimoNespolo (talk | contribs) (Created page with "A primitive basis a, b, c is called a ‘reduced basis’ if it is right-handed and if the components of the metric tensor satisfy the conditions below. Because of [[lattice]...")
A primitive basis a, b, c is called a ‘reduced basis’ if it is right-handed and if the components of the metric tensor satisfy the conditions below. Because of lattice symmetry there can be two or more possible orientations of the reduced basis in a given lattice but, apart from orientation, the reduced basis is unique. The type of a cell depends on the sign of
T = (\mathbf{a}\cdot\mathbf{b})(\mathbf{b}\cdot\mathbf{c})(\mathbf{c}\cdot\mathbf{a}).
If T > 0, the cell is of type I, if T ≤ 0 it is of type II.
The conditions for a primitive cell to be a reduced cell can all be stated analytically as follows:
Contents
[hide]Type-I cell
Main conditions
- \mathbf{a}\cdot\mathbf{a} ≤ \mathbf{b}\cdot\mathbf{b} ≤ \mathbf{c}\cdot\mathbf{c}
- |\mathbf{b}\cdot\mathbf{c}| ≤ (\mathbf{b}\cdot\mathbf{b})/2
- |\mathbf{a}\cdot\mathbf{c}| ≤ (\mathbf{a}\cdot\mathbf{a})/2
- |\mathbf{a}\cdot\mathbf{b}| ≤ (\mathbf{a}\cdot\mathbf{a})/2
- \mathbf{b}\cdot\mathbf{c} \gt 0
- \mathbf{a}\cdot\mathbf{c} \gt 0
- \mathbf{a}\cdot\mathbf{b} \gt 0
Special conditions
- if \mathbf{a}\cdot\mathbf{a} = \mathbf{b}\cdot\mathbf{b} then \mathbf{b}\cdot\mathbf{c} ≤ \mathbf{a}\cdot\mathbf{c}
- if \mathbf{b}\cdot\mathbf{b} = \mathbf{c}\cdot\mathbf{c} then \mathbf{a}\cdot\mathbf{c} ≤ \mathbf{a}\cdot\mathbf{b}
- if \mathbf{b}\cdot\mathbf{c} = (\mathbf{b}\cdot\mathbf{b})/2 then \mathbf{a}\cdot\mathbf{b} ≤ 2\mathbf{a}\cdot\mathbf{c}
- if \mathbf{a}\cdot\mathbf{c} = (\mathbf{a}\cdot\mathbf{a})/2 then \mathbf{a}\cdot\mathbf{b} ≤ 2\mathbf{b}\cdot\mathbf{c}
- if \mathbf{a}\cdot\mathbf{b} = (\mathbf{a}\cdot\mathbf{a})/2 then \mathbf{a}\cdot\mathbf{c} ≤ 2\mathbf{b}\cdot\mathbf{c}
Type-II cell
Main conditions
- \mathbf{a}\cdot\mathbf{a} ≤ \mathbf{b}\cdot\mathbf{b} ≤ \mathbf{c}\cdot\mathbf{c}
- |\mathbf{b}\cdot\mathbf{c}| ≤ (\mathbf{b}\cdot\mathbf{b})/2
- |\mathbf{a}\cdot\mathbf{c}| ≤ (\mathbf{a}\cdot\mathbf{a})/2
- |\mathbf{a}\cdot\mathbf{b}| ≤ (\mathbf{a}\cdot\mathbf{a})/2
- (|\mathbf{b}\cdot\mathbf{c}|+ |\mathbf{a}\cdot\mathbf{c}|+|\mathbf{a}\cdot\mathbf{b}|) ≤ (\mathbf{a}\cdot\mathbf{a}+\mathbf{b}\cdot\mathbf{b})/2
- \mathbf{b}\cdot\mathbf{c} ≤ 0
- \mathbf{a}\cdot\mathbf{c} ≤ 0
- \mathbf{a}\cdot\mathbf{b} ≤ 0
Special conditions
- if \mathbf{a}\cdot\mathbf{a} = \mathbf{b}\cdot\mathbf{b} then |\mathbf{b}\cdot\mathbf{c}| ≤ |\mathbf{a}\cdot\mathbf{c}|
- if \mathbf{b}\cdot\mathbf{b} = \mathbf{c}\cdot\mathbf{c} then |\mathbf{a}\cdot\mathbf{c}| ≤ |\mathbf{a}\cdot\mathbf{b}|
- if |\mathbf{b}\cdot\mathbf{c}| = (\mathbf{b}\cdot\mathbf{b})/2 then \mathbf{a}\cdot\mathbf{b} = 0
- if |\mathbf{a}\cdot\mathbf{c}| = (\mathbf{a}\cdot\mathbf{a})/2 then \mathbf{a}\cdot\mathbf{b} = 0
- if \mathbf{a}\cdot\mathbf{b} = (\mathbf{a}\cdot\mathbf{a})/2 then \mathbf{a}\cdot\mathbf{c} = 0
- if (|\mathbf{b}\cdot\mathbf{c}|+ |\mathbf{a}\cdot\mathbf{c}|+|\mathbf{a}\cdot\mathbf{b}|) = (\mathbf{a}\cdot\mathbf{a}+\mathbf{b}\cdot\mathbf{b})/2 then \mathbf{a}\cdot\mathbf{a} ≤ 2|\mathbf{a}\cdot\mathbf{c}|+ |\mathbf{a}\cdot\mathbf{b}|